Integrand size = 16, antiderivative size = 10 \[ \int \frac {x^2}{3+4 x^3+x^6} \, dx=-\frac {1}{3} \text {arctanh}\left (2+x^3\right ) \]
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Leaf count is larger than twice the leaf count of optimal. \(21\) vs. \(2(10)=20\).
Time = 0.01 (sec) , antiderivative size = 21, normalized size of antiderivative = 2.10, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.188, Rules used = {1366, 630, 31} \[ \int \frac {x^2}{3+4 x^3+x^6} \, dx=\frac {1}{6} \log \left (x^3+1\right )-\frac {1}{6} \log \left (x^3+3\right ) \]
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Rule 31
Rule 630
Rule 1366
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \text {Subst}\left (\int \frac {1}{3+4 x+x^2} \, dx,x,x^3\right ) \\ & = \frac {1}{6} \text {Subst}\left (\int \frac {1}{1+x} \, dx,x,x^3\right )-\frac {1}{6} \text {Subst}\left (\int \frac {1}{3+x} \, dx,x,x^3\right ) \\ & = \frac {1}{6} \log \left (1+x^3\right )-\frac {1}{6} \log \left (3+x^3\right ) \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(21\) vs. \(2(10)=20\).
Time = 0.00 (sec) , antiderivative size = 21, normalized size of antiderivative = 2.10 \[ \int \frac {x^2}{3+4 x^3+x^6} \, dx=\frac {1}{6} \log \left (1+x^3\right )-\frac {1}{6} \log \left (3+x^3\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. \(17\) vs. \(2(8)=16\).
Time = 0.04 (sec) , antiderivative size = 18, normalized size of antiderivative = 1.80
method | result | size |
default | \(-\frac {\ln \left (x^{3}+3\right )}{6}+\frac {\ln \left (x^{3}+1\right )}{6}\) | \(18\) |
risch | \(-\frac {\ln \left (x^{3}+3\right )}{6}+\frac {\ln \left (x^{3}+1\right )}{6}\) | \(18\) |
norman | \(\frac {\ln \left (x +1\right )}{6}-\frac {\ln \left (x^{3}+3\right )}{6}+\frac {\ln \left (x^{2}-x +1\right )}{6}\) | \(27\) |
parallelrisch | \(\frac {\ln \left (x +1\right )}{6}-\frac {\ln \left (x^{3}+3\right )}{6}+\frac {\ln \left (x^{2}-x +1\right )}{6}\) | \(27\) |
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Leaf count of result is larger than twice the leaf count of optimal. 17 vs. \(2 (8) = 16\).
Time = 0.25 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.70 \[ \int \frac {x^2}{3+4 x^3+x^6} \, dx=-\frac {1}{6} \, \log \left (x^{3} + 3\right ) + \frac {1}{6} \, \log \left (x^{3} + 1\right ) \]
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Time = 0.05 (sec) , antiderivative size = 15, normalized size of antiderivative = 1.50 \[ \int \frac {x^2}{3+4 x^3+x^6} \, dx=\frac {\log {\left (x^{3} + 1 \right )}}{6} - \frac {\log {\left (x^{3} + 3 \right )}}{6} \]
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Leaf count of result is larger than twice the leaf count of optimal. 17 vs. \(2 (8) = 16\).
Time = 0.20 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.70 \[ \int \frac {x^2}{3+4 x^3+x^6} \, dx=-\frac {1}{6} \, \log \left (x^{3} + 3\right ) + \frac {1}{6} \, \log \left (x^{3} + 1\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 19 vs. \(2 (8) = 16\).
Time = 0.30 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.90 \[ \int \frac {x^2}{3+4 x^3+x^6} \, dx=-\frac {1}{6} \, \log \left ({\left | x^{3} + 3 \right |}\right ) + \frac {1}{6} \, \log \left ({\left | x^{3} + 1 \right |}\right ) \]
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Time = 0.21 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.60 \[ \int \frac {x^2}{3+4 x^3+x^6} \, dx=\frac {\mathrm {atanh}\left (\frac {9}{2\,\left (8\,x^3+6\right )}+\frac {5}{4}\right )}{3} \]
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